You are assigned the design of a cylindrical, pressurized water tank for a futur

Question

You are assigned the design of a cylindrical, pressurized water tank for a future colony on Mars, where the acceleration due to gravity is 3.71 meters per second per second. The pressure at the surface of the water will be 140 kPa , and the depth of the water will be 14.5 m . The pressure of the air in the building outside the tank will be 88.0 kPa .

Find the net downward force on the tank's flat bottom, of area 1.60 m2 , exerted by the water and air inside the tank and the air outside the tank.

Express your answer numerically in Newtons, to three significant figures.

Explanation / Answer

preesure at the bottom of the tank, P_bottom = P_surface + rho*g*h

= 140*10^3 + 1000*3.71*14.5

= 193795 pa

pressure outside, P_out = 88*10^3 pa

so, net downward force      = (P_bottom - P_out)*A

= (193795-88*10^3)*1.6

= 1.69*10^5 N

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.