a monochromatic a light with a wavelength of 600 nm passes through a single slit

Question

a monochromatic a light with a wavelength of 600 nm passes through a single slit which has a width of 0.800 mm. what is the distance between the slit and the screen be located if the first minimum in the diffraction pattern is at a distance of 1.00 mm from the center of the screen a monochromatic a light with a wavelength of 600 nm passes through a single slit which has a width of 0.800 mm. what is the distance between the slit and the screen be located if the first minimum in the diffraction pattern is at a distance of 1.00 mm from the center of the screen a monochromatic a light with a wavelength of 600 nm passes through a single slit which has a width of 0.800 mm. what is the distance between the slit and the screen be located if the first minimum in the diffraction pattern is at a distance of 1.00 mm from the center of the screen

Explanation / Answer

The general condition for destructive interference is

sintheta = m*lambda/a

For small , we employ the approximation sintheta=tantheta y/L which yields

y/l= m*lambda/a

The first minimum corresponds to m=1. If y = 1.00 mm then

l = 8*10^-4*1*10^-3/600*10^-9*1 = 1.33 m

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