The 10-cm-wide, zero-resistance slide wire shown in the figure is pushed toward

Question

The 10-cm-wide, zero-resistance slide wire shown in the figure is pushed toward the 2.0? resistor at a steady speed of 0.50 m/s. The magnetic field strength is 0.30 T

Part B: What is the magnitude of the induced current in the slide wire?

Part D: What is the magnitude of the magnetic force?

Part E: What is the magnitude of the pushing force?

Part F: How much power is dissipated in the resistor?

Part G: What is the energy dissipated in the resistor in 2 mins?

Part H: What is the work done by the pushing force in 2 mins?

Explanation / Answer

induce emf , e = vBL = 0.5*0.30*0.10 = 0.015 volt

a) induce current , i = 0.015/2.0 = 7.5 mA

b) magnetic force , F = BiL =0.30*7.5*10^-3*0.1 = 0.225*10^-3 N

c) since constant speed

so pushing force = magnetic force = 0.225*10^-3 N

d) power dissipated in the resistor , P = i^2*R = (7.5*10^-3)^2*2.0 = 112.5*10^-6 w

e) energy dissipated = P*t = 112.5*10^-6*2*60 = 13.5 mJ

f) W = F*D = 0.225*10^-3*0.5*2*60 = 13.5 mJ

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