Assignment Submission For this assignment, you submit answers by question parts.

Question

Assignment Submission For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer. Assignment Scoring Your last submission is used for your score. A "seconds" pendulum is one that goes through its equilibrium position once each second. (The period of the pendulum is 2.000 s.) The length of a seconds pendulum is 0.9927 m at Tokyo an 0.9942 m at Cambridge, England. What is the ratio of the free-fall accelerations at these two locations? (Give your answer to at least 4 decimal places.) Cambridge/Tokyo =

Explanation / Answer

let the acceleration in Tokyo is g1

acceleration in Cambridge is g2

L1 = 0.9927 m

L2 = 0.9942 m

as time period of pendulum is given as

T = 2 pi * sqrt(L/g)

for the time period of both pendulum to be same

2 pi * sqrt(L1/g1) = 2pi * sqrt(L2/g2)

0.9927/g1 = 0.9942/g2

g2/g1 = 1.0015

the ratio Cambridge/Tokyo is 1.00151

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