A 1.5-cm object is placed 0.50 m to the left of a diverging lens with a focal le
ID: 1512760 • Letter: A
Question
A 1.5-cm object is placed 0.50 m to the left of a diverging lens with a focal length of 0.20 m. Aconverging lens with a focal length of 0.17 m is located 0.08 m to the right of the diverging lens.70. What is the location of the final image with respect to the object?A) The final image is located 0.14 m to the left of the object.B) The final image is located 0.32 m to the right of the object.C) The final image is located 0.40 m to the right of the object.D) The final image is located 0.83 m to the right of the object.E) The final image is located 1.3 m to the right of the object
(answer is E)
71. What is the height and orientation with respect to the original object of the final image?A) 1.4 cm, invertedB) 1.4 cm, uprightC) 0.95 cm, invertedD) 0.95 cm, uprightE) 0.28 cm, inverted
answer is A
please explain
Explanation / Answer
diverging lens f = -0.20
1/di = 1/f - 1/do
di = -1/7 meter
m = -di/do = 0.286
now this image will be object for converging lens
do = 1/7 + 0.08 = 0.223 m
1/di = 1/f - 1/do
di = 0.717 m
m = -0.717/0.223 = -3.206
image distance = 0.717 + 0.08 + 0.5 = 1.3 m to the right of the object
part 71 )
image height = -3.206 * 0.429 = -1.4 cm
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