REFLECT The hydraulic lift is a force-amplifying device. The amplification facto

Question

REFLECT The hydraulic lift is a force-amplifying device. The amplification factor is the ratio of the areas of the pistons. It seems as though we get something for nothing. But the much greater weight is lifted through a much smaller distance, and the two quantities of work are the same m magnitude. The device amplifies force, but it can't amplify energy Engineers are designing a hydrautic kit that can be used to repair trucks with a mass of 5800 kg. What ratio of piston areas would you suggest for the design it the maximum available external force is to be 3000 N ? Express your answer to three significant figures

Explanation / Answer

From Pascal's law : P = F/A = constant => F1/A1  = F2/A2

A2/A1  = F2/F1   = mg/3000 = 5800*9.81/3000 = 18.966

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