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11. [2pt] A point charge Q moving perpendicular to a magnetic field of 1.10 T di

ID: 1514052 • Letter: 1

Question

11. [2pt]
A point charge Q moving perpendicular to a magnetic field of 1.10 T directed INTO the page experiences a force of 8.00×10-12 N directed towards the top the page. Which of the following statements is correct? (Give ALL correct answers, eg. B, AC, BCD...)

A) Q is positive moving to the left
B) Q is negative moving to the left
C) Q is positive moving to the right
D) Q is positive moving out of the page
E) None of the above

Answer:  


12. [2pt]
A 0.54 cm high object is placed 8.8 cm in front of a diverging lens with a focal length of -7.2 cm. What is the height of the image formed by this lens?

Answer:  


13. [2pt]
The focal length of a concave mirror is 16.5 cm. If an object is located 39.5 cm in front of this mirror, how far in front of the mirror will the image be located?

Answer:  


14. [2pt]
An object is placed 39.5 cm in front of a concave mirror with a focal length of 16.5 cm. What will the magnification be?

Answer:  


15. [2pt]
A source with a surface area of 3.8 cm^2 produces 1.60 W of acoustical power and projects this uniformly in all directions. What will the sound intensity be at a distance of 130.00 cm from the source?

Explanation / Answer

here,

11)

magnetic feild is INTO the page

force is towards topof the page

using right hand rule,

then the correct statments are

B) Q is negative to the left

C) Q is positive to the right

12)

height of object , ho = 0.54 cm

object distance , do = 8.8 cm

focal length , f = - 7.2 cm

let the image distance be di

using the lens formula

1/f = 1/di +1/do

- 1/7.2 = 1/di + 1/8.8

di = - 3.96 cm

hi/ho = - di/do

hi/0.54 = 3.96/8.8

hi = 0.243 cm

the height of image is 0.243 cm

13)

object distance , do = 39.5 cm

focal length , f = 16.5 cm

let the image distance be di

using the lens formula

1/f = 1/di +1/do

1/16.5 = 1/di + 1/39.5

di = 16.5 cm


the distance of image is 16.5 cm

14)

object distance , do = 39.5 cm

focal length , f = 16.5 cm

let the image distance be di

using the lens formula

1/f = 1/di +1/do

1/16.5 = 1/di + 1/39.5

di = 16.5 cm

magnification , m = -di/do

m = - 16.5 /39.5

m = - 0.42