help with 11.2 please. may you please show step by step solution please with uni
ID: 1514114 • Letter: H
Question
help with 11.2 please.
may you please show step by step solution please with units.
aced its center of gravity, Hou far fror the lem fnlcrum placed just under its center of just under its center of gravity, How far horiaontaly a fulcrum placed os wi far fro the11 11.2" The center of grav ity of a 5.00-kg irregular ob- efi eed should the fulcrum be placed shoule center of gra- Figure E11.2 ct is shown in Fig. E11.2 You need to move the center of gravity 2.20 em to the left by gluing on a 1.50-kg mass which will then be considered antys as part of the object. Where sbould the center of gravity of this additional mass be kcadhel 11.3 . A uniform rod is 2.00 m long and has mass 150 A sen 2.40-kg clamp is attached to the rod. How far should the cener o gravity of the clamp be from the left-hand end of the rod in onder friti for the center of gravity of the composite object to be 1.30 m from lali the left-hand end of the rod Section 11.3 Solving Rigid-Body Equlibrium Problems iul 114.A uniform MXAN trapdoor in a floor is hinged alone frie de. Find the net upward force noeded to begia lo open i and i the sotal force exerted on the door by the hinges ias if the upwand frce torce is applied at the center and (b) it the upward force is apled t the center of the edge opposite the hinges 11.5 Raising a Ladder. A ladder carried by a fire tnak s long. The ladder weighs 3400 N and its censer of gaviy tongue at the pin. The luder is s at its center IFig, E:1.5 ore er. The ladder is pivoted at one end (A) about . Ell.s), ignore the friction taised into to Position by a force applied by a bydranlic Ptsa make." 8.0 m1 from A, and the force F eseried by ite isin Poin 11.12 s an angle of 40P with the ladšer What mgat i ave to just lift the ladder off the support free-body diagram int C is 80 m from A, and the force Pe rt bracket at Agure E11.5 12.0 mExplanation / Answer
given
Xcm = 2.2cm
we know that
Xcm = 5x 0 + (1.5x L)/6.5
2.2 = 15L/65
L = 9.533 cm
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