The answer to these two questions are 1 and 5, please show steps how to get to t

Question

The answer to these two questions are 1 and 5, please show steps how to get to those

Just prior to r = 0. the capacitor (C = 1 times 10^-3 F) in the circuit below has a charge of 1 pC. The inductor has inductance. L = 1 times 10^-6 H. At r=0, a switch (no: shown) is dosed, allowing current to flow around the circuit. What is the magnitude of the current when Referring to the above circuit, at the instant when die charge on die capacitor has fallen to 0.5 pC. what is the magnitude of the rate of change in current?

Explanation / Answer

part 10 )

dI/dt = Q/LC

dI/dt = 0.5uC/10^-9 = 500 A/s

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