I am having a hard time trying to solve part C of Mastering Physics Problem 8.22

Question

I am having a hard time trying to solve part C of Mastering Physics Problem 8.22

The tires of a car make 93 revolutions as the car reduces its speed uniformly from 85.0 km/h to 59.0 km/h. The tires have a diameter of 0.88 m. What was the angular acceleration of the tires? Express your answer using two significant figures. Part B If the car continues to decelerate at this rate, how much more time is required for it to stop? Express your answer to two significant figures and include the appropriate units. Part C How far does the car go? Find the total distance. Express your answer to three significant figures and include the appropriate units.

Explanation / Answer

theta = 93 rev = 93*2*3.14 = 584.04 rad

v1 =85 km/h = 23.6 m/s

v2 = 59 km/h = 16.39 m/s

d = 0.88 m , r =0.44 m

alpha = -1.3 rad/s^2,

a = r*alpha

from kinematic equations

v2^2 - v1^2 = 2as

(16.39)^2 - (23.6)^2 = -2*0.44*1.3*s

s = 252 m

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