The 100 mu F capacitor on the right is filled with a dielectric with k = 4. What
ID: 1517484 • Letter: T
Question
The 100 mu F capacitor on the right is filled with a dielectric with k = 4. What is the charge on and voltage across the capacitor? If you removed the dielectric while leaving the battery connected, what are the capacitor's new capacitance, charge and voltage? Discuss the flow of charge in the circuit while you are pulling out the dielectric. Suppose you disconnect the battery and then reinsert the dielectric. What are the new capacitance, charge, and voltage for the capacitor? Discuss the flow of charge in the circuit while you are inserting the dielectric.Explanation / Answer
a) capacitor is connected with 10 V voltage.
hence voltage across capacitor will be 10 Volt. . ...Ans
and Q = C V
Q = 100 x 10^-6 x 10 = 1 x 10^-3 C Or 1 mC
b) C' = C/k = 100 uF / 4 = 25uF
voltage will be same as 10 V as it is still connecetd.
and Q = C' V = 25 x 10^-6 x 10 = 0.25 x 10^-3 C Or 0.25 mC
as dielectric is pulled, voltage cross capacitor become more than 10 V (of battery), so charge
flow from capacitor to battery.
c) when battery is diconnected before then charge on capacitor will be constant.
Q = 0.25 mC
C will be again 100 uF .
and Q = C V
0.25 x 10^-3 = (100 x 10^-6)V
V = 2.5 Volt
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