A circular ammeter has a radius of 2.50 cm. The ring of the ammeter is capable o

Question

A circular ammeter has a radius of 2.50 cm. The ring of the ammeter is capable of measuring the magnetic field they are subject to. When the ammeter is clamped around a wire carrying a direct current, as shown in the figure, the average value of the magnetic field measured in the sides is 4.00 G. what is the current in the wire? A long solenoid (diameter of 6.00 cm) is wound with 1500 turns per meter of thin wire through which a current of 0.250 A is maintained. A wire carrying a current of 12.0 A is inserted along the axis of the solenoid. What is the magnitude of the magnetic field at a point 1.50 cm from the axis?

Explanation / Answer

we can use the formula here as

B*perimeter of ammerer =mu*I

where mu the permeability constant (µ0), also known as the magnetic constant or the permeability of free space value µ0 = 4 × 107 H.

So, I = B x 2pie x r / mu = 4.0 x 10^-4 x 2xpiex 2.5 x 10^(-2) m / 4 pi x 10^-7

or, I = %0 A.

for the next question please type the question seperately.Please dont leave in negative feedback if you have any doubt just let me know. Thanks.

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