A The x coordinate of an electron is measured with an uncertainty of 0.200 mm .

Question

A

The x coordinate of an electron is measured with an uncertainty of 0.200 mm . What is vx , the x component of the electron's velocity, if the minimum percentage uncertainty in a simultaneous measurement of vx is 1.00 % ? Use the following expression for the uncertainty principle:

where x is the uncertainty in the x coordinate of a particle, px is the particle's uncertainty in the x component of momentum, and =h2, where h is Planck's constant.

Answer

Part B= Repeat part A for a proton.

help please

Part B= Repeat part A for a proton.

help please

Explanation / Answer

for electron,

deltax . deltap = h/ 2pi

(0.2 x 10^-3) ( m deltav ) = (6.626 x 10^-34 ) / (2pi)

m = 9.109 x 10^-31 kg ...mass of electron

delta v = 0.579

and deltav = v x 1 / 100

v = 0.579 x 100 = 57.9 .........Ans

for proton :

(0.2 x 10^-3) ( m deltav ) = (6.626 x 10^-34 ) / (2pi)

m = 1.67 x 10^-27 kg ...mass of proton

delta v = 3.157 x 10^-4 m/s

and deltav = v x 1 / 100

v = 3.157 x 10^-4 x 100 = 0.03157 m/s .........Ans

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