A force table has a force on the central ring in the +x-direction of a magnitude

Question

A force table has a force on the central ring in the +x-direction of a magnitude of 25N another force acting at 30 degrees to the +x- direction with a magnitude of 45N. What force needs to be applied to the ring, and in what direction, so that the ring is stationary? A force table has a force on the central ring in the +x-direction of a magnitude of 25N another force acting at 30 degrees to the +x- direction with a magnitude of 45N. What force needs to be applied to the ring, and in what direction, so that the ring is stationary?

Explanation / Answer

here,

Force, f1x = 25 N

Force F2x = 45*Cos30 = 38.971 N
Force, F2y = 45*Sin30 = 22.5 N

Net force in z direction, Fx = 25 + 38.971 = 63.971 N
Net Force in y direction, Fy = 22.5 N

Net magnitude of force,
F = sqrt(fx^2 + fy^2)
F = sqrt(63.971^2 + 22.5^2)
F = 67.813 N

Direction, A = arcTan(Fy/Fx) = arcTan(22.5/63.971) = 19.378 degrees above + x axis

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