A positive charged 3.5 Times 10^-8 C is 10.0 mm from a negative charge of 4.3 Ti

Question

A positive charged 3.5 Times 10^-8 C is 10.0 mm from a negative charge of 4.3 Times 10^-8 C. The magnitude of the electric force on one charge due to the other is If 15 Amperes is flowing in a circuit, how many Coulombs of charge pass a given point on 1/2 hour? A 1500w device is connected to a 120V electrical outlet. What is the current through this device? A 200 ohm resistor and a 20 ohm resistor are connected in series. What is the equivalent resistance of the combination? How much energy (in Joules) is stored in a 10 mu f capacitor if the potential across it is 25V?

Explanation / Answer

11)

F = kQ1Q2/r^2

F = 9*10^9*3.5*10^(-6)*4.3*10^(-6)/(10*10^(-3))^2 = 1354.5 N

12)

I = 15 amp

Q/t = 15

Q = 15*(1/2)*60*60 = 27000 C

13)

P = 1500 W

V = 120 volt

P = V*I

I = 1500/120 = 12.5 amp

14)

equivalent resistance = 200 + 20 = 220 ohm

15)

energy = (1/2)CV^2 = (1/2)*10*10^(-6)*(25)^2 = 0.003125 J

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