A snapshot of the wave traveling to the right at 1 cm/s is shown at time t = 1 s
ID: 1520013 • Letter: A
Question
A snapshot of the wave traveling to the right at 1 cm/s is shown at time t = 1 sec. Draw the snapshot (in the picture itself) at the wave at t = 0 seconds and 3 seconds. What is the direction of motion (upward or downward) in the y-direction of the following points at the instant shown (i.e, t=1 second)? (Explain how you arrived at your answer.) x = 1 cm, x = 3 cm, x = 5 cm, x = 7 cm What is the height (position on the y axis) of the particle on the rope at x = 4 cm, at time t = 2, 3,4 and 6 seconds? Explain how you determined these values. A wave in a string is described by D(x, t) = 2.6cm Sin [(x/7.2) + 2 pi (t/0.2) + 1] where x is in m and t is in s. Answer the following questions. Which way is the wave traveling? What are the time period and wavelength of the wave? What is the velocity of the wave? What is the displacement of the string at x = 3.6 m and t = 1 s? A concert loudspeaker suspended high off the ground emits sound. A small microphone with an area of 0.8 cm^2 is 50.0 m from the speaker gets a sounds energy of 8.91 times 10^-8 Joules each second. Find the intensity of the sounds at the microphone. What is the power of the speaker What is the decibel level of the speaker?Explanation / Answer
Problem 1)
A) The diagram drawn is correct.
B) When we will draw shape at t=1+delta where delta is very small, and compare the value of y at t=1 and at t=1+delta at the given value of x
a) downward,
b)upward
c) upward
d) downward
C) At t=2 y= 0.5 cm.....because at t=2, the shape will start at x=1, and achieve its maxima (y=1cm) at x=3
At t =3, y= 1 cm......because at t=3, the shape will start at x=2, and achieve its maxima (y=1cm) at x=4
At t=4, y=0.5cm......because at t=4, the shape will start at x=3, and achieve its maxima (y=1cm) at x=5
At t=6, y = 0 ......because at t=6, the shape will start at x=5, and achieve its maxima (y=1cm) at x=7
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.