Two masses are connected by a string as shown in the figure. Mass mA = 2.9 kg re

Question

Two masses are connected by a string as shown in the figure. Mass mA = 2.9 kg rests on a frictionless inclined plane, while mB = 4.8 kg is initially held at a height of h = 0.90 m above the floor.

A. If mB is allowed to fall, what will be the resulting acceleration of masses?

B.If the masses were initially at rest, use the kinematic equations to find their velocity just before mB hits the floor.

C.Use conservation of energy to find the velocity of the masses just before mB

Problem 8.22 Two masses are connected by a string as shown in the figure. Mass mA 2.9 kg rests on a frictionless inclined plane, while mB = 4.8 kg is initially held at a height of h = 0.90 m above the floor. (Figure 1) Figure 1of 1 MA mB = 32°

Explanation / Answer

T = Ma*Mb*g[1+sin]/(Ma + Mb) = (2.9*4.8*9.8(1+sin32))/(2.9+4.8)= 27.1 N

A. a = (Mb*g - T)/Mb = (4.8*9.8-27.1)/4.8=4.154 m/s²

B. V = [2*a*h] =[2*4.154*0.9] = 2.734 m/s

C. Mb*g*h - Ma*g*h*sin = ½(Ma+Mb)*V²
..V2 = 2*(4.8*9.8*0.9-2.9*9.8*0.9*sin32)/(2.9+4.8) =7.4757 m/s

V = 2.7341 m/s

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