Res light(lambda = 633 nm) is shining through two slits that are 0.05 mm apart.

Question

Res light(lambda = 633 nm) is shining through two slits that are 0.05 mm apart. The interference pattern is observed on a screen 3 m away. Determine how tar from the center line the second-order bright fringe will be observed. is shining at an angle onto a flat glass window (n = 1.52). Under which incident angle will the reflected light be completely polarized? (The surrounding medium is air with n = 1.00). If the reflected light is vertically polarized, at which angle do you have to adjust the polarizing axis of a linear polarizer to obtain half the intensity? To eliminate the reflection the glass is coated with a thin-film antireflection coating

Explanation / Answer

1 For constructive interference, the path difference is a multiple of the wavelength:

d*sin Q = m(lambda) .

We find the location on the screen from

y = L tan Q

For small angles, we have

Sin Q ~ TanQ which gives

y = mL(lambda)/d

For the second order, we have

y = (3 * 633e-9 * 2)/(0.05e-3) = 0.07596 m = 75.96 mm

2) at Brewster angle
tan Q = n2/n1 = 1.5/1
Q = 56.66rad

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