Res previous | Aluminum reacts with chlorine gas to form aluminum chloride via t

Question

Res previous | Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction 2A1(s) + 3C12 (g)--2A1Cla (s) You are given 26.0 g of aluminum and 31.0 g of chlorine gas Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 26 0 g of aluminum? Express your answer to three significant figures and include the appropriate units. Hints 38.86 g Submit My Answers Give Up Incorrect: Try Again; 4 attempts remaining Part B if you had excess aluminum how many moles of aluminum chloride could be produced from 31.0 g of chlorine gas Cl2? Express your answer to three significant figures and include the appropriate units 9

Explanation / Answer

Molecular weight of Al is 26.982 g

Given the condition is that excess chlorine is given so Al is the limiting reagent.

2 moles of aluminium (2 * 26.982 g) will form 2 moles (2*133.34 g) of AlCl3

i.e 53.964 g Al produces 266.68 g AlCl3

26 g of Al produces (26 g * 266.68 g)/53.964 g Al = 128.487 g (for three significant digits)

Related Questions

Navigate

• Browse (All)
• Browse R
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.