MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEXT Chapter 02, Problem

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MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEXT Chapter 02, Problem 034 In the figure here, a red car and a green car move toward each other in adjacent lanes and to time t 0, red car is at xr 0 and the green car is at x9 212 m. If the red car has a constant velocity of 28.0 km/h, the cars pass each other at X 44,5 m. On the other hand, if the red car has a constant velocity of 56.0 km/h, they pass each other at x 76.6 m. What are (a) the initial velocity and (b) the (constant) acceleration of the green car? Include the signs. (a) Number Unit (b) Number click if you would like to show work for this questiona open show work Question Attempts: o of 6 used SAVE FOR LATER SUBMIT ANSwnR Copyright 2000-2017 by John Wiley sons, inc or reiated companies Airghii reserved. Au Rights Reserved. A Diviskan or 2ahn MacBook Air

Explanation / Answer

Assuming initial velocity of green car = v & acceleration = a

In intial case

Vr = 28km/h = 28*1000/3600 = 7.77 m/s

t = 44.5/(7.77) = 5.72 s

distance travelled by green car = 212-44.5 = 167.5 m

=> 167.5 = v*(5.72) + (1/2)*a*(5.72)2 ----------- eqn 1

In Second case

Vr = 56km/h = 15.55m/s

t = 76.6/(15.55) = 4.926s

Distance travelled by green car = 212 - 76.6 = 135.4 m

=> 135.4 = v*(4.926) + (1/2)*a*(4.926)2 -------- eqn 2

Solving eqn 1 & 2

And find v and a.

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