The initial velocity of a ball launched into free fall is: v i = 16.35 m/s and ?

Question

The initial velocity of a ball launched into free fall is: vi = 16.35 m/s and ?i = 32°.

(c) Calculate the maximum height hmax of the ball.

(d) Calculate the horizontal distance R (range) of the ball.

5. The initial velocity of a ball launched into free fall is: Vi- 16.35 m/s and 32 CA (a) Calculate the X and y components of the initial velocity. Vxo 13.86559 m/s vyo 8.6642 m/s (b) Calculate the total time of flight total of the ball. total 1.76820 (c) Calculate the maximum height h of the ball. max X m max (d) Calculate the horizontal distance R (range) of the ball. X m

Explanation / Answer

here,

vi = 16.35 m/s

theta = 32 degree

c)

let the maximum height of the ball be hmax

for vertical direction

v^2 - u^2 = 2 * hmax * g

16.35^2 = 2 * hmax * 9.8

hmax = 13.64 m

the maximum height is 13.64 m

d)

time of flight , t = 1.7682 s

the horizontal range of the ball , x = vi * cos(theta) * t

x = 16.35 * cos(32) * 1.7682 m

x = 24.5 m

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