1/25/2017 11:55 PM A 15.5/18 1/25/2017 o7:52 PM Gradebook e Print calculator Per

Question

1/25/2017 11:55 PM A 15.5/18 1/25/2017 o7:52 PM Gradebook e Print calculator Periodic Table Question 15 of 18 Incorrect Incorrect Incorrect Map A Sapling Learning A proton is released from rest inside a region of constant, uniform electric field E1 pointing due North. 22.3 seconds after it is released, the electric field instantaneously changes to a constant, uniform electric field E2 pointing due South. 4.71 seconds after the field changes, the proton has returned to its starting point. What is the ratio of the magnitude of E2 to the magnitude of E? You may neglect the effects of gravity on the proton. Number Tools x 10 O Previous Check Answer Next Exit H Hint

Explanation / Answer

Here ,

t1 = 22.3 s

t2 = 4.71 s

for the acceleration of the charge , it is directily proporational to Electric field

hence ,

Now, Using second equation of motion

0.5 * E1 * t1^2 = - E1 * t1 * t2 + 0.5 * E2 * t2^2

0.5 * 22.3^2 * E1 = - E1 * 22.3 * 4.71 + 0.5 * E2 * 4.71^2

solving for E2/E1

E2/E1 = 31.9 = 3.19 *10^1

the ratio of magnitude of E2 to E1 is 3.19 *10^1

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