Background pertinent to this problem is available in Interactive LearningWare 18

Question

Background pertinent to this problem is available in Interactive LearningWare 18.3. A uniform electric field exists everywhere in the x, y plane. This electric field has a magnitude of 4800 N/C and is directed in the positive x direction. A point charge -9.4 × 10-9 C is placed at the origin. Find the magnitude of the net electric field at (a) x = -0.16 m, (b) x = +0.16 m, and (c) y = +0.16 m. Background pertinent to this problem is available in Interactive LearningWare 18.3. A uniform electric field exists everywhere in the x, y plane. This electric field has a magnitude of 4800 N/C and is directed in the positive x direction. A point charge -9.4 × 10-9 C is placed at the origin. Find the magnitude of the net electric field at (a) x = -0.16 m, (b) x = +0.16 m, and (c) y = +0.16 m.

Explanation / Answer

here,

electric feild , E0 = 4800 i N/C

q = - 9.4 * 10^-9 C

a)

at x = -0.16 m

electric feild due to q , E = k * q/x^2 i

E = 9 * 10^9 * 9.4 * 10^-9 /0.16^2

E = 3304.69 i N/C

the magnitude of net electric feild , E' = E + E0

E' = 8104.7 N/C

b)

at x = 0.16 m

electric feild due to q , E = - k * q/x^2 i

E = - 9 * 10^9 * 9.4 * 10^-9 /0.16^2 i

E = - 3304.69 i N/C

the magnitude of net electric feild , E' = E + E0

E' = 1495.31 N/C

c)

at y = 0.16 m

electric feild due to q , E = - k * q/x^2 j

E = - 9 * 10^9 * 9.4 * 10^-9 /0.16^2 j

E = - 3304.69 j N/C

the magnitude of net electric feild , E' = sqrt(E^2 + E0^2 )

E' = 5827.6 N/C

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