Interactive Learningware 18.2 provides one approach to solving problems such as

Question

Interactive Learningware 18.2 provides one approach to solving problems such as this one. The drawing shows three point charges fixed in place The charge at the coordinate has value of v_1 = + 11.5 mu C; the other two have identical magnitudes, but opposite signs: q_2 = -5.54 mu C and q_3 = + 5.54 mu C. (a) Determine the net force exerted on q_1 by the other two charges. (b) If q_1 had a mass of 1.50 g and it were free to move, what would be its acceleration? Number units Number Units Click if you would like to show work for this question:

Explanation / Answer

Here,

for the electric force at the charge q1 due to q2

F12 = 9 *10^9 * 11.5 *10^-6 * 5.54 *10^-6/1.30^2

F12 = 0.34 N

as the electric force at the q1 due to q3

F12 = 9 *10^9 * 11.5 *10^-6 * 5.54 *10^-6/1.30^2

F12 = 0.34 N

for the net force at q1

Fnet = 2 * F12 * sin(theta)

Fnet = 2 * 0.34 * sin(23)

Fnet = 0.27 N

the net force exerted on q1 is 0.27 N

b)

m = 1.50 gm = 0.0015 kg

let the acceleration is a

a * 0.0015 = 0.27

a = 176.8 m/s^2

the acceleration is 176.8 m/s^2

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