Two charges are located in the x-y plane. if q1= -2.90 nC and is located at x= 0

Question

Two charges are located in the x-y plane. if q1= -2.90 nC and is located at x= 0.00 m, y= 1.200 m and the second charge has magnitude of q2= 3.40 nC and is located at x= 1.50 m, y= 0.550 m, calculate the x and y components, Ex and Ey, of the electric field, E, in component form at the origin, (0,0). The Coulomb Force constant is 8.99 X 10^9 N•m^2/C^2

Two charges are located in the X yplane. If q 2.90 nC and is located at x F 0.00 m, y 1.200 m and the second charge has magnitude of q2E 3.40 nCand is located at x E 1.50 m, y E 0.550 m, calculate the x and y components, Ex and Ey, of the electric field, E, in component form at the origin, (0,0). The Coulomb Force constant is 1/(41TEO) 8.99 x 109 N. m2/c2. Number Number

Explanation / Answer

r1=1.2m , r2= sqrt(1.5^2 + 0.55^2) = 1.59m

= tan^-1(0.55/1.5) = 20 deg

E1 = kq1/r1^2 = (9*10^9*2.90*10^-9)/(1.2^2) = 18.1N/C directed along + y axis, towards q1

E1x = 0 N/C

E2y= 18.1 N/C

E2 = kq2/r2^2 = (9*10^9*3.4*10^-9)/(1.592) = 12.1N/C directed away from the q2

E2x= -E2cos = - 12.1*cos20 = -11.37 N/C

E2y= -E2sin = - 12.1*sin20 = -4.13N/C

Ex = E1x + E2x = 0 -11.37 =   -11.37 N/C

Ey = E1y + E2y = 0 = 18.1 - 4.13 = 13.9 N/C

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