Two charged beads are on the plastic ring in part (a) of the figure below. Bead
ID: 2043576 • Letter: T
Question
Two charged beads are on the plastic ring in part (a) of the figure below. Bead 2, which is not shown, is fixed in place on the ring, which has radius R = 46.0 cm. Bead 1 is initially at the right side of the ring, at angle = 0°. It is then moved to the left side, at angle = 180°, through the first and second quadrants of the xy coordinate system. Part (b) of the figure gives the x component of the net electric field produced at the origin by the two beads as a function of . Similarly, part (c) of the figure gives the y component.
(a) At what angle is bead 2 located? (Assume that it is located in the lower half of the ring.)
_________°
(b) What is the charge of bead 1?
_________C
(c) What is the charge of bead 2?
_________C
Explanation / Answer
a) The bead b is located at below the horizontal axis, so from the figure bead b might be located at 270o. b) From the graph b the magnitude of force is F = 5x104 N. this indicate that at = 0, the component is only due to bead 1. Electric field is given as E = k q / r2 5x104 N = (8.99x109) q / (0.46)2 q = 1.77x10-6 C c) From the graph b the magnitude of force is F = 9x104 N. this indicate that at = 90, the component is only due to bead 2. Electric field is given as E = k q / r2 9x104 N = (8.99x109) q / (0.46)2 q = -2.118x10-6 C ( component is negative as the bead is located at below the horizontal axis) Electric field is given as E = k q / r2 9x104 N = (8.99x109) q / (0.46)2 q = -2.118x10-6 C ( component is negative as the bead is located at below the horizontal axis)
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