Three charged marbles are glued to a nonconducting surface and are placed in the

Question

Three charged marbles are glued to a nonconducting surface and are placed in the diagram as shown. The charges of each marble are q1 = 5.65 µC, q2 = 1.69 µC, and q3 = 1.53 µC. Marble q1 is a distance r1 = 3.00 cm to the left of the marble q2, while marble q3 is a distance r3 = 2.00 cm to the right of the marble q2, as shown. Calculate the magnitude of the electric field a distance r' = 1.00 cm to the left of the center marble.

Another marble is placed 1 cm to the left of the middle marble. If this new marble has a charge of 3.74 µC,calculate magnitude and direction of the force on it

magnitude?

direction?

Explanation / Answer

a) The field at the observation point will be sun of individual fields of the charges.

E = E1 + E2 + E3

Field due to q1 is positive and for q3 as well but for q2 its negative.

E = k (q1/r1^2 - q2/r2^2 + q3/r3^2)

E = 9 x 10^9 x 10^-6 (5.65/0.02^2 - 1.69/0.01^2 + 1.53/0.03^2) = -9.68 x 10^6 N/C

Hence, E = 9.68 x 10^6 N/C

b) We know that,

F = qE

F = -3.74 x 10^-6 x 9.68 x 10^6 = -36.23 N

Hence, F = -36.23 N

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.