Two point charges q_1 = +2.15nC and q_2 = -6.25nC are 0.100 m apart. Point A is

Question

Two point charges q_1 = +2.15nC and q_2 = -6.25nC are 0.100 m apart. Point A is midway between them; point B is 0.080 m from q_1 and 0.060 m from q_2 (See (Figure 1).) Take the electric potential to be zero at infinity. Find the potential at point A Express your answer in volts to three significant figures. V = _______ Find the potential at point B Express your answer in volts to three significant figures. V = ___________ Find the work done by the electric field on a charge of 2 25 nC that travels from point B to point A Express your answer in joules to two significant figures. W = ___________

Explanation / Answer

here,

electric potential due to charge at point is given by expression;

V = k * SUM(q/r)

where r is distance to point

Part a:

V = k * (q1/r1 + q2/r2)

V = 9*10^9 * ((2.15*10^-9)/0.05 + (-6.25*10^-9/0.05)

V = -738 V

Part b:

V = k * (q1/r1 + q2/r2)

V = 9*10^9 * ((2.15*10^-9)/0.08 + (-6.25*10^-9/0.06)

V = -695.625 V

part c :

charge, q = 2.25*10^-9 C

Work done, W = -Q(Vfinal - Vinitial)

work done, W = - 2.25*10^-9 * (-695.625 - 738)

work done, W = 3.226*10^-6 J

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