The scalar product of vectors A and B is +56.0 m2 . Vector A has magnitude 9.00

ID: 1527034 • Letter: T

Question

The scalar product of vectors A and B is +56.0 m2 . Vector A has magnitude 9.00 m and direction 28.0 west of south.

Part A

If vector B has direction 39.0 south of east, what is the magnitude of B ?

Express your answer with the appropriate units.

The scalar product of vectors A and B is +56.0 m2 . Vector A has magnitude 9.00 m and direction 28.0 west of south.

Part A

If vector B has direction 39.0 south of east, what is the magnitude of B ?

Express your answer with the appropriate units.

B =

here,

A = 9 * ( - sin((28)) - cos(28) j)

A = (- 4.23 i - 7.95 j) m

let the magnitude of B be B'

B = B' * ( cos(39) i - sin(39) j)

B = B' * ( 0.777 i - 0.63 j) m

A .B = 56 m^2

(-4.23 i - 7.95 j) * B' *(0.777 i - 0.63 j) = 56

B' = 32.5 m

the magnitude of b is 32.5 m

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.