Question Part Points Submissions Used A baby elephant is stuck in a mud hole. To

Question

Question Part Points Submissions Used A baby elephant is stuck in a mud hole. To help pull it out, game keepers use a rope to apply a force F with arrowA, as part a of the drawing shows. By itself, however, force F with arrowA is insufficient. Therefore, two additional forces F with arrowB and F with arrowC are applied, as in part b of the drawing. Each of these additional forces has the same magnitude F. The magnitude of the resultant force acting on the elephant in part b of the drawing is k times larger than that in part a. Find the ratio F FA when k = 2.20. (Take = 21.0°.)

Explanation / Answer

In part (a)

The magnitude if force F_a = F_A

In part (b)

The magnitude of force is F_b =k times larger than part a = k * F_a = F_A + x component of (F_B + F_C)

k*F_A = F_A + cos () (F_B + F_C)

2.2 * F_A= F_A + (cos(21))(2F)

1.2F_A = 0.9336*2F

F/F_A = 0.64267

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