Question Part Points Submissions Used A 9.06-kg hanging weight m 2 is connected

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Question Part Points Submissions Used

A 9.06-kg hanging weight m2 is connected by a string over a pulley to a 5.00-kg block m1 that is sliding on a flat table. If the coefficient of kinetic friction is 0.194, find the tension in the string Question Part Points Submissions Used

A 9.06-kg hanging weight m2 is connected by a string over a pulley to a 5.00-kg block m1 that is sliding on a flat table. If the coefficient of kinetic friction is 0.194, find the tension in the string Question Part Points Submissions Used

Question Part Points Submissions Used

Question Part Points Submissions Used

Question Part Points Submissions Used Question Part Points Submissions Used A 9.06-kg hanging weight m2 is connected by a string over a pulley to a 5.00-kg block m1 that is sliding on a flat table. If the coefficient of kinetic friction is 0.194, find the tension in the string A 9.06-kg hanging weight m2 is connected by a string over a pulley to a 5.00-kg block m1 that is sliding on a flat table. If the coefficient of kinetic friction is 0.194, find the tension in the string A 9.06-kg hanging weight m2 is connected by a string over a pulley to a 5.00-kg block m1 that is sliding on a flat table. If the coefficient of kinetic friction is 0.194, find the tension in the string Question Part Points Submissions Used

Explanation / Answer

for the 9.06 kg :
m2g - T = m2a
9.06(9.8) - T = 9.06a
88.788 - T = 9.06a ---eq.1

for the 9 kg :

T - m1g(0.194) = m1a

T - 9.506 = 5a --- eq.2

Adding eq.1 and eq.2,

88.788 - 9.506 = 14 a

so a = 5.663 m/s2

and T = 5a + 9.506= 37.821 N

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