Example 11-9 depicts the following scenario. A cat walks along a plank with mass

Question

Example 11-9 depicts the following scenario. A cat walks along a plank with mass M = 5.00 kg. The plank is supported by two sawhorses. The center of mass of the plank is a distance d_1 = 0.850 m to the left of sawhorse B. When the cat is a distance d_2 =1.11 m to the right of sawhorse B, the plank just begins to tip. Now we will consider a slightly different scenario related to Example 11-9. Part A If the cat has a mass of 3.9 kg, how far to the right of sawhorse B can it walk before the plank begins to tip?

Explanation / Answer

the plank will tip when torque by the weight of the cat about B

is greater than torque by the weight of the plank.

so at the given scenario, both the torque values are equal.

then m*g*d2=M*g*d1

given m=3.9 kg

M=5 kg

d1=0.85 m

we need to find d2.

d2=M*d1/m=1.08974 m

in 2 significant figures, answer will be 1.1 m.

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