A +18 nC charge is located at the origin. What is the electric field at the posi

Question

A +18 nC charge is located at the origin. What is the electric field at the position (x_1, y_1) = (50 cm, 0 cm)? Write electric field vector in component form. Enter the x and y components of the electric field separated by a comma. What is the electric field at the position (x_2, y_2) = (-5.0 cm, 5.0 cm)? Write electric field vector in component form. Enter the x and y components of the electric field separated by a comma. What is the electric field at the position (x_3, y_3) = (-5.0 cm, -5.0 cm)? Write electric field vector in component form. Enter the x and y components of the electric field separated by a comma.

Explanation / Answer

(A)

q = 18 nC

r = 0.05 m i

Ex = k*q / r^2

Ex = 9*10^9*18 / (0.05)^2 = 6.5*10^4 N/C

(Ex , Ey) = (6.5*10^4i , 0) N/C

(B)

at (-5 cm , 5 cm)

r = sqrt(5^2 + 5^2) = 0.0707 m

E = 9*10^9*18 / (0.0707)^2 = 3.24*10^4 N/C

Ex = 3.24*10^4*cos45 = -2.29*10^4 i

Ey = 2.29*10^4 j

(Ex , Ey) = (-2.29*10^4i , 2.29*10^4j)N/C

(C)

at (-5 cm , -5 cm)

E = 3.24*10^4 N/C

(Ex , Ey = -2.29*10^4i , -2.29*10^4j) N/C

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