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secure l httpsallusq45bxtheexpertta.com/Common Take TutorialAssignment aspx Home Student: qtran5@mailstmaryto edu Log out My Account Class Management I Help Homework 2 Begin Date: 2017 11:00 00 PM Due Date: 2/5/2017 11 00:00 PM End Date: 2 is 201712 00:00 AM Problem 7: One strategy when on a diet is to drink ice water The body must calones to warm the water from 0°C to a of c Assume a dieter drinks e ofice every day. The specific of water is 4.186 x bod 103 C). 50% Part How much energy. un joules, does the dieter's body need to provide un order to warm the water over a full year. Take 365 days in a year. 50% Part a) One pound of fat supplies 3600 kcal (cal) to the body, where 1 kcal cal 4186 x 103 J How much fat, in pounds can the dieter hope to lose in a year by drinking ice water rather than water at body temperature? Grade Suuwary Completed Completed sin0 4 5 6 Completed atano acotar sinho Completed Hints deduction ver hint Hints remaining: deduction per feedback

Explanation / Answer

First of all heat required to change 0 degree water to body temperature is given by H=m*S*T

where S= specific heat and T= temperature difference

using values heat energy for 1 day= H= 2.9 *4.186*10^3*(37-0)J =449.16*10^3 J

for 1year heat energy required 365H = 365*449.16*10^3 J =163942.6*10^3J

b) 1 pound of fat= 3600* 4.186*10^3 J fat

Therefore 3600* 4.186*10^3 J energy burning means 1pound fat burning

1J energy burning means1/3600* 4.186*10^3 pound fat burning

163942.6*10^3Jenergy burning means1/3600* 4.186*10^3* 163942.6*10^3 pounds fat burning = 10.879pounds

So total fat can be burned in one year is= 10.879pounds

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