charge of 28.0 nC is placed in a uniform electric field that is directed vertica

Question

charge of 28.0 nC is placed in a uniform electric field that is directed vertically upward and has a magnitude of 4.30×104 V/m .

Part A

What work is done by the electric force when the charge moves a distance of 0.490 m to the right?

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Part B

What work is done by the electric force when the charge moves a distance of 0.720 m upward?

charge of 28.0 nC is placed in a uniform electric field that is directed vertically upward and has a magnitude of 4.30×104 V/m .

Part A

What work is done by the electric force when the charge moves a distance of 0.490 m to the right?

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SubmitMy AnswersGive Up

Correct

Part B

What work is done by the electric force when the charge moves a distance of 0.720 m upward?

Explanation / Answer

1) here angle between displacement and force is = 90º because force is upward and displacement is to the right .
So, electrostatic Force, F= q E = 28X10^-9 x 4.30×10^4
= 1.204x10^-3 N
So workdone, W = Fd cos90º = 0 joule

2) here = 0º
So workdone, W = Fd cos0º = 1.204x10^-3 x 0.72 joule
=8.67x10^-4 joule

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