3rd time asking this question. please don\'t answer if you are not sure. Everyth

Question

3rd time asking this question. please don't answer if you are not sure. Everything is correct but part D.

A ball is shot from the ground into the air. At a height of 9.1 m, the velocity is observed to be [v with arrow] = (7.7 [i hat] + 5.9 [j] ) m/s, with [i hat] horizontal and [j] upward.
(a) What is the velocity of the ball immediately after it is shot? Put your answer in unit vector notation.
7.7 m/s [i hat] + 14.6 m/s [j]
(b) To what maximum height does the ball rise?
10.87 m

(c) What total horizontal distance does the ball travel?
22.93m

(d) What is the magnitude of the ball's velocity just before it hits the ground?
16.51 m/s

(d) What is the direction of the ball's velocity just before it hits the ground?
____???? ° counterclockwise from the + [i hat] direction ***answer is not 117.8 or 117.79

Explanation / Answer

Horizontal component of velocity does not change at all and vertical component decreases to 0 at maximum height and then again increases to the same value in the opposite direction.

Hence velocity just before it hits the ground = 7.7 I -14.6 j

And the angle with +i direction = tan-1 (14.6/7.7) = 62.193 degree clockwise

And hence 360 - 62.193 = 297.807 degree counter clockwise.

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