A +20 nC charge is located at the origin. What is the electric filed at the posi

Question

A +20 nC charge is located at the origin. What is the electric filed at the position (x_1, y_2) = (5.0 cm, 0 cm)? Write electric field vector is component form. Enter the x and y components of the electric field separated by a comma. What is the electric field at the position (x_2, y_2) = (-5.0 cm, 5.0 cm)? Write electric field vector in component form. Enter the x and y components of the electric field separated by a comma. What is the electric field at the position (x_2, y_3) = (-5.0 cm, -5.0 cm)? Write electric field vector in component form. Enter the x and y components of the electric field separated by a comma.

Explanation / Answer

part b )

r1 = -5x + 5y

ro = 0x + 0y

r1 - r0 = r = -5x + 5y

|r|= sqrt(5^2+5^2)

|r| = 0.0707 m

E = kq*r/|r|^3

E = 9*10^9 * 20 * 10^-9 * (-0.0707x + 0.0707)/0.0707^3

E = -36010.88x + 36010.88y

Ex = -36010.88 N/C = 3.6 x 10^4 N/C

Ey = 36010.88y N/C = 3.6 x 10^4 N/C

part c )

r1 = -5x - 5y

r0 = 0x + 0y

r1 - r0 = -5x - 5y

r = -5x - 5y

|r| = sqrt(-5^2+-5^2)

|r| = 0.0707 m

E = kq*r/|r|^3

E = 9*10^9 * 20 * 10^-9 * (-0.0707x -0.0707y)/0.0707^3

E = -36010.88x - 36010.88y

Ex = -36010.88 N/C = -3.6 x 10^4 N/C

Ey = -36010.88y N/C = -3.6 x 10^4 N/C

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