Four capacitors are arranged in the circuit shown in the figure. The capacitors

Question

Four capacitors are arranged in the circuit shown in the figure. The capacitors have the values C1 = 30.5 F, C2 = 45.5 F, C3 = 50.5 F, C4 = 40.5 F, and the power supply is at voltage V = 34.5 V. What is the equivalent capacitance of the circuit?

Four capacitors are arranged in the circuit shown in the figure. The capacitors have the values C1 30.5 UF, C2 -45.5 UF, C3 50.5 yF C4 40.5 UF, and the power supply is at voltage V 34.5 V. What is the equivalent capacitance of the circuit? Number What is the charge on capacitor C2? Number What is the potential difference across capacitor C3 Number What is the potential energy stored in capacitor C4? Number

Explanation / Answer

C3 and C4 are connected in parallel.

equivalent capacitance=C3+C4=91 uF

it is in series with C1 and C2.

if equivalent capacitance is C,

then 1/C=(1/C1)+(1/C2)+(1/91)

==>1/C=(1/30.5)+(1/45.5)+(1/91)=0.065754

==>C=15.2082 uF

so equivalent capacitance is 15.2082 uF

part B:

net charge on equivalent capacitance=voltage*capacitance

=524.683 uC

as charge on capacitors connected in series is equal,

charge on C1=charge on C2=524.683 uC

part C:

from part B,

charge on parallel combination of C3 and C4 (i.e. 91 uF) is 524.683 uC

voltage across parallel combination=charge/capacitance

=5.7657 volts

so voltage across C3=5.7657 volts

part D:

voltage across C4=voltage across C3=5.7657 volts

then potential energy stored in C4=0.5*C4*voltage^2

=0.5*40.5*10^(-6)*5.7657^2=6.7317*10^(-4) J

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.