NOTE: IT IS QUESTION 3.2 White-collar crime a. You are a city inspector. You go
ID: 1529588 • Letter: N
Question
NOTE: IT IS QUESTION 3.2
White-collar crime a. You are a city inspector. You go undercover to a bakery and buy 30 loaves of bread marked 500 g. Back at the lab you weigh them and find their masses to be 493, 503, 486, 489, 501, 498, 507, 504, 493, 487, 495, 498, 494, 490, 494, 490, 497, 503, 498, 495, 503, 496, 492, 492, 495, 498, 490, 490, 497, and 482 g. You go back to the bakery and issue a warning. Why? b. Later you return to the bakery (this time, they know you). They sell you 30 more loaves of bread. You take them home, weigh them, and find their masses to be 504, 503, 503, 503, 501, 500, 500, 501, 505, 501, 501, 500, 508, 503, 503, 500, 503, 501, 500, 502, 502, 501, 503, 501, 501, 502, 503, 501, 502, and 500 g. You're satisfied, because all the loaves weigh at least 500 g. But your boss reads your report and tells you to go back and close the shop down. What did she notice that you missed? Relative concentration versus altitude Earth's atmosphere has roughly four molecules of nitrogen for every oxygen molecule at sea level; more precisely, the ratio is 78:21. Assuming a constant temperature at all altitudes (not really very accurate), what is the ratio at an altitude of 10 km? Explain why your result is qualitatively reasonable.Explanation / Answer
N( h ) = No exp ( - m g h / k T )
the molecular mass of Oxygen is MN2 = 0.032 kg / mol
the molecular mass of Nitrogen is MO2 = 0.028 kg / mol
R = 8.31 J / K . mol
at sea Level
no of molecules of N2 / no of molecules of O2 = 78 / 21
NN2 ( 1 km ) / NO2 ( 1 km ) = 78/21 ( MN2 -MO2 ) 10 km / R T
NN2 ( 1 km ) / NO2 ( 1 km ) = 4.36
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.