A spherical conductor has a radius of 14.0 cm and a charge of 70.0 µC. Calculate

Question

A spherical conductor has a radius of 14.0 cm and a charge of 70.0 µC. Calculate the electric field and the electric potential at the following distances from the center.

spherical conductor has a radius of 14.0 cm and a charge of 70.0 HC. Calculate the electric field and the electric potential at the following distances from the center. tial (a) r 8.0 cm direction magnitude MN/C there is no direction electric field 0 d MV outward electric potential 7.64 (b) r 26.0 cm magnitude direction MN/C Select electric field MV --Select- electric potential (c) r 14.0 cm direction magnitude MNyc Select electric field MV -Select electric potential

Explanation / Answer

given

R = 14 cm = 0.14 m

Q = 70.0 micro C

a) at r = 8 cm = 0.08 m ( < R)

E = 0 (since, In elctrostatic equilibrium inside a conductor E is always zero.)

V = k*Q/R

= 9*10^9*70*10^-6/0.014

= 4.50*10^7

= 45.0 MV (No direction)

b)

at r = 26 cm = 0.26 m ( > R)

E = k*Q/r^2

= 9*10^9*70*10^-6/(0.26^2)

= 9.32*10^6 N/C

= 9.32 MN/C (radially outward)

V = k*Q/r

= 9*10^9*70*10^-6/0.026

= 2.42*10^7

= 24.2 MV (No direction)

C)

at r = 14 cm = 0.26 m ( = R)

E = k*Q/r^2

= 9*10^9*70*10^-6/(0.14^2)

= 3.21*10^7 N/C

= 32.1 MN/C (radially outward)

V = k*Q/r

= 9*10^9*70*10^-6/0.026

= 2.42*10^7

= 24.2 MV (No direction)

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