Consider P = 330 N and Q = 430 N. Determine the magnitude and direction of the r

Question

Consider P = 330 N and Q = 430 N. Determine the magnitude and direction of the resultant of the two forces) The magnitude of the resultant of the two forces is (Round the final answer to the nearest whole number) The direction of the resultant of the two forces in the x-direction is (Round the final answer to a single decimal place:) The direction of the resultant of the two forces in the y-direction is (Round the final answer to a single decimal) The direction of the resultant of the two forces in the z-direction is (Round the final answer to a single decimal places)

Explanation / Answer

Qy = Q Sin50 = 430 Sin50 j = 329.4 j

Qx = (Q Cos50) Cos20 = (430 Cos50) Cos20 = 259.73 i

Qz = - (Q Cos50) Sin20 k = - (430 Cos50) Sin20 = - 94.5 k

similarly

Py = P sin30 j = 330 Sin30 j = 165 j

Pz = (P Cos30) Cos15 = (330 Cos30) Cos15 = 276.1 k

Px = - (P Cos30) Sin15 = - (330 Cos30) Sin15 = - 73.97 i

P = - 73.97 i + 165 j + 276.1 k

Q = 259.73 i + 329.4 j - 94.5 k

Net force is given as

F = P + Q = (- 73.97 i + 165 j + 276.1 k ) + (259.73 i + 329.4 j - 94.5 k)

F = 185.76 i + 494.4 j + 181.6 k

magnitude : sqrt((185.76)2 + (494.4)2 + (181.6)2) = 558.5 N

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.