In the lab you tested a simple circuit made of a battery connected to a light bu

Question

In the lab you tested a simple circuit made of a battery connected to a light bulb. You measured the current flowing through the light bulb and your typical result looked like the following graph. How do you explain a spike in the current for a brief period of time after the switch connecting light bulb to the battery was closed? Light bulb filament has significant capacitance which draws a lot of current from the battery until it is fully charged Light bulb filament acts as a large inductance and produces a large emf opposing the voltage change from the battery after the switch is closed Light bulb has some electric charge stored in it from being previously connected to a battery so it takes a short transient time for these charges to drain from the bulb Light bulb obeys the Ohm's law only after the current settles into a steady state and the resistance of the light bulb decreases Light bulb does not obey the Ohm's law and as the current settles into a steady state the

Explanation / Answer

Correct option: Light bulb obeys the Ohm’s law only after the current settles into a steady state and the resistance of the light bulb decreases

Current in the circuit develops only when the switch is closed. As the switch is closed current flows through the bulb filament but as soon as the switch is closed charge carriers face large resistance and it obeys Ohm’s law V=IR when the resistance of the circuit gets steady.

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