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Two 10-cm-diameter charged rings face each other, 19 cm apart. The left ring is

ID: 1531424 • Letter: T

Question

Two 10-cm-diameter charged rings face each other, 19 cm apart. The left ring is charged to -15 nC and the right ring is charged to +15 nC .

Part A: What is the magnitude of the electric field E  at the midpoint between the two rings?

Part B: What is the direction of the electric field E  at the midpoint between the two rings?

To the right ring.

Parallel to the plane of the rings

To the left ring

Part C: What is the magnitude of the force F  on a -1.0 nC charge placed at the midpoint?

Part D: What is the direction of the force F  on a -1.0 nC charge placed at the midpoint?

To the right ring

To the left ring

Parallel to the plane of the rings

Explanation / Answer

a )

given

d = 19 cm = 0.19 m

Q = 15 n C

D = 10 cm

R = D / 2 = 5 cm = 0.05 cm

the net elecgric field is

Enet = K Q d / ( (d/2)2 + R2 )3/2  

Enet = 9 X 109 X 15 X 10-9 X 0.19 / ( 0.19/2 )2 + 0.052 )3/2   

Enet = 20731.27 N/C

b )

the Enet is in directed towards the center of the negative charged ring or positive X - direction

c )

F = q Enet

F = - 1 X 10-9 X 20731.27

F = - 20731.27 X 10-9 N

d )

here in this case

the Enet is

the charge at the midpoint is negative the electric force on this particle directs to center of positive charge ring.

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