Continuing on from problem 4, we\'ll do some calculations. Calculate the positio

Question

Continuing on from problem 4, we'll do some calculations. Calculate the positions of all locations (a finite distance from the charges) on the x-axis where the net electric field is zero. Calculate the positions of all locations (a finite distance from the charges) on the x-axis where the net electric potential is zero. At a location where the net electric field is zero, what (if anything) docs that imply about the net electric potential at that location? The potential is also zero the slope of the potential vs. position graph is zero Neither of these at a location where the net electric potential is zero, what (if anything) does that imply about the net electric field at that location? The electric field is also zero the slope of the electric field vs. position graph is zero Neither of these

Explanation / Answer

Given charged

   27*10^-9 C -------------------3*10^-9 C
here the electric field will be zero near the smaller charge so the field is zero either to the left or right side that

at left side the field dierection of +27 nC charge is to the right and with -3nC chargeis also to the right side so there is no possibility of zero electric field

and the right side to the -3nC is field dierection of +27 nC charge is to the right and with -3nC chargeis also to the left side so there is possibility of zero electric field

that is at +1 position
  
  

E1 = kq1/r1^2 = 9*10^9*(27*10^-9))/(3)^2 N/C= 27 N/C

   E2 = kq2/r2^2 = 9*10^9*(-3*10^-9)/(1)^2 N/C = -27 N/C

at the other positions the field never zero

--------------------

potential

   v = kq/r

   kq/x = kq2/(2-x)

   27/x = -3/(2-x)

solving for x , x = 2.25 m

so the potential will be zero at 2.25 m from 27 nc charge that is 0.25 m to the right of -3 nC charge

Part C

potentail at +1 m is

   kq1/r2 +kq2/r2 = k(q1/r1+q2/r2)

       = 9*10^9((27*10^-9)/3)+((-3*10^-9)/1) V

           = 54 V
Neither of these

Part C

   E at x = 0.25 m from q2 , due two chages is

   E1 = kq1/r1^2 = 9*10^9*(27*10^-9))/(2.25)^2 N/C= 48 N/C

   E2 = kq2/r2^2 = 9*10^9*(-3*10^-9)/(0.25)^2 N/C = -432 N/C
E = 48-432 = -384 N/C

neither of these

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.