A soccer ball is kicked with an initial horizontal velocity of 13 m/s and an ini

Question

A soccer ball is kicked with an initial horizontal velocity of 13 m/s and an initial vertical velocity of 21 m/s. 1) What is the initial speed of the ball? 24.70 m/s Submit 2) What is the initial angle of the ball with respect to the ground? 58.2 degrees Submit Your submissions: 58.2 Computed value:58.2Submitted:Tuesday, February 14 at 12:30 AM Feedback:Correct! 3) What is the maximum height the ball goes above the ground? m Submit 4) How far from where it was kicked will the ball land? m Submit 5) What is the speed of the ball 2.1 seconds after it was kicked? m/s Submit

Explanation / Answer

step;1

Given that

initial horizantal velocity ux=13 m/s

initial vertical velocity uy=21 m/s

step;2

now we find the initial speed

initial speed u=[13^2+21^2]^1/2=24.7 m/s

step;3

now we find the angle

angle=tan^-1[21/13]=58.2 degree

step;4

now we find the maximum height

the maximum height =24.7^2*sin^2(58.2)/2*9.8

=124.83 m

step;5

now we find the range

the range R=24.7^2*sin(2*58.2)/9.8

=55.8 m

step;6

now we find the velocity after time t=2.1 s

the finial velocity v=24.7+9.8*2.1=45.3 m/s

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