It was shown in Example 21.11 (Section 21.5) in the textbook that the electric f

Question

It was shown in Example 21.11 (Section 21.5) in the textbook that the electric field due to an infinite line of charge is perpendicular to the line and has magnitude E = lambda/2pi epsilon_0r, Consider an imaginary cylinder with a radius of r = 0.130 m and a length of l = 0.425 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is lambda = 4.35 mu C/m. What is the electric flux through the cylinder due to this infinite line of charge? What is the flux through the cylinder if its radius is increased to r = 0.540 m? What is the flux through the cylinder if its length is increased to l = 0.820 m?

Explanation / Answer

electric flux = E*A*costheta

part(A)

theta = 0

A = surface area of cylinder = 2*pi*r*L

r = radius of cylinder

l = length of the cylinder

E = electric field due to infinite wire = lambda/(2*pi*e0*r)

flux = lambda/(2*pi*e0*r))*2*pi*r*L

flux = lambda*L/e0

flux = 4.35*10^-6*0.425/(8.85*10^-12) = 2.1*10^5 Nm^2/C            <<<<<==============answer

======================

part B

flux = 4.35*10^-6*0.425/(8.85*10^-12) = 2.1*10^5 N m^2/C            <<<<<==============answer

remains same

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part C

flux = 4.35*10^-6*0.82/(8.85*10^-12) = 4.03*10^5 N m^2/C        <<<<<==============answer

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