F1: 18 N @ 27 degree counter-clockwise from + y axis F2: 1.47 N @ 30 degree cloc
ID: 1532581 • Letter: F
Question
F1: 18 N @ 27 degree counter-clockwise from + y axis F2: 1.47 N @ 30 degree clockwise from -y axis F3: 0.98 N @ 8 degree counterclockwise from -y axis When you have completed this activity, please list and clearly label the answers to the following questions under the bold, boxed-in heading Results and Conclusions, being careful to answer all questions in complete sentences: List the three forces that you were given, including both magnitude and direction. What magnitude and direction did you calculate for the resultant force? What magnitude and direction did you calculate for the equilibrant force? List the angles at which you positioned the pulleys and the total mass that you suspended from each pulley. Did your calculated equilibrant force agree with the actual value? (In this case, we are asking if the ring was centered on the post without touching it when you applied the three assigned forces and the calculated equilibrant force.)Explanation / Answer
let i and j be unit vectors along +ve x and +ve y axis
then F1=1.18*(-sin(27) i+ cos(27) j)
=-0.5357 i +1.0514 j
F2=1.47*(-sin(30) i-cos(30) j)
=-0.735 i -1.2731 j
F3=0.98*(sin(8) i - cos(8) j)
=0.1364 i -0.9705 j
Q1. forces are F1, F2 and F3 as described in the question.
Q2.
resultant=F1+F2+F3
=-1.4071 i -1.1922 j
magnitude= sqrt(1.4071^2+1.1922^2)=1.8443 N
angle with +ve x axis=220.2738 degrees in anticlockwise direction
Q3.equilibriant force=-(resultant force)
=1.4071 i + 1.1922 j
magnitude=1.8443 N
angle with +ve x axis=40.2738 degrees
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