F-8N 60 o A block of weight 19.6 N rests on a horizontal surface. If a force of
ID: 1789869 • Letter: F
Question
F-8N 60 o A block of weight 19.6 N rests on a horizontal surface. If a force of 8 N is angle of 60 to the horizontal in the direction shown, the block just begns 0 the normal tortss exerted by the surface on the block. (b) After the block starts sliding, ONLY a single force of 4 N applied horzontaly to applied to it at an rection shown, the block just begins to slide. Find i of static friction between the block and the surface and (il) 6 points the left (and no other force) is needed to keep it in motion at constant speed. () friction. (ii) Is the normal force the same as it was in part Find (a)? If not, what is it? the coefficient of kinetic 14 points A separate marked is required for each part. clearly labelled free body diagram with all forces and components propertExplanation / Answer
A) ii) Normal =19.6 + 8 sin 60 degree = 26.53 N
i) Friction = 8 cos 60 degree = 4 N
usN = friction
us* 26.53 = 4
Coefficient of static friction us = 4/26.53 = 0.1508
B) again Normal N = 19.6 N
Friction =4N
uk N = friction
uk*19.6 = 4
Coefficient of kinetic friction uk = 4/19.6
= 0.204
ii) Normal = 19.6N
Not same as in a
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