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F Facebook x Labradoodles vs. Golde x MVSecure File Transfer Se xA c Chegg Study I Guided morgan M Inbox morgan d.lyt Bb Chapter 3 Displaying Vanderbilt University ng.com 2418976 Bookmarks D I Am Not Yours z Pla If Facebook M Inbox morgan.d.l D wish a Amazon.com: Cnline t umblr Oth My Assignment Resources /19/2016 11:55 PM A 93.8/100 1/18/2016 07:59 PM Gradebook Assignment Information Attempts Score fee Prin Calculator Available From /5/2016 06:00 PM 00 Question 3 of 16 Due Date: 1/19/2016 11:55 PM Map 00 Points Possible 00 Grade Category Graded Vector Chas a magnitude 27.0 m and is in the direction of the negative y-axis. Vectors Aand Bare at angles a 42.4 and B 26.2 up from the x-axis respectively. If the vector sum A+ B+C 0, what are Description: the magnitudes of A and B? 00 Rericha HW2 Policies: 00 You can check your answers. You can keep trying to answer each questio 00 you get it right or give up You can view solutions after the extended A 37.35 00 date. There is no penalty for incorrect answers. 00 O eTextbook Numb BI- 1767 00 O Help With This Topic 00 Web Help & Videos 00 O Technical Support and Bug Reports 00 Previous Check Answer Next I Exit 00 Think about the implication for the components of the three vectors given that the vector sum of all three 00 adds to zero. 00 Copyright 20 2016 Sapling Learning, Inc.-217 about us privacy policy terms of use Contact u help partners careers

Explanation / Answer

x- and y- components of vector A, B and C are

Ax = |A| * cos42.4 and Ay= |A| * sin42.4

Bx = - |B|* cos26.2 and By = |B| sin26.2

Cx = |C|* cos90=0 and Cy = - |C| sin90 = - 27.0 m

Since A+B+C = 0   impleis that Ax + Bx + Cx = 0   => |A| * cos42.4 - |B|* cos26.2 + 0 = 0

=> |A| * cos42.4 = |B|* cos26.2 => |A|= |B|* cos26.2/cos42.4 => |A| = 1.215 *|B| ..................(i)

Also, Ay + By + Cy = 0 => |A| * sin42.4 + |B| sin26.2 -27 = 0

=> 1.215*|B| * sin42.4 + |B| sin26.2 -27 = 0 => |B|*(1.215* sin42.4 + sin26.2) = 27

|B| = 27 / (1.215* sin42.4 + sin26.2) = 21.4 m

Magnitude of B, |B| = 21.4m

Plug in the value of |B| in (i)   , |A| = 1.215 * 21.4 = 26.0 m

Hence magnitude of A, |A| = 26.0 m

and magnitude of B, |B| = 21.4 m

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