A coil has a magnetic dipole moment of 0.144 A middot m^2 directed to the left (

Question

A coil has a magnetic dipole moment of 0.144 A middot m^2 directed to the left (leftarrow). It is in a huge uniform external magnetic field of 45 T directed toward the bottom (downarrow). Find the torque the huge field exerts on the coil. I find the magnitude using I use phi = (Put symbols in the four blanks above.) (Write a number above for phi.) A straight wire segment is 2.54 cm long and carries a substantial current of 99 A toward the top (uparrow) through a huge uniform external magnetic field of 45 T directed toward the bottom (downarrow). Find the force exerted by the field on the segment. I find the magnitude using I use phi = (Put symbols in the five blanks above.) (Write a number above for phi.) A uniform magnetic field makes an angle of 20.0 degree with a flat surface. Thus it makes an angle of 90.0 degree - 20.0 degree = 70.0 degree with the normal to the surface. The area of the surface is 5.55 times 10^-5 m^2. The resulting magnetic flux through the surface is 57.0 nWb. Calculate the magnitude of the magnetic field to three significant figures. We see the edge of a 45 turn flat circular coil of magnetic dipole moment 0.144 A middot m^2 in magnitude. The eye (not ours) looks along the coil's axis, "seeing" a counterclockwise current of 6.4 A. Find the coil's area vector. (The "DIRECTION" answer is relative to the paper, not relative to the eye, so answer "right (rightarrow)" or "left (leftarrow)".) An electron is moving out of the paper at 2.46 times 10^8 m/s through a huge external magnetic field of 45 T directed toward the bottom (downarrow). Find the force the huge field exerts on the electron. I find the magnitude using I use phi = (Put symbols in the five blanks above.) (Write a number above for phi.) In this problem, the direction of v times B is

Explanation / Answer

here,

the magnetic dipole moment , m = 0.144 A.m^2

the uniform external magnetic feild , B = 45 T

the torque exerted on the coil , t = m X B

t = 0.144 * 45 N.m

t = 6.48 N.m

the torque exerted on the coil is 6.48 N.m

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